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12010344301021 = 111091849481911
BaseRepresentation
bin1010111011000110000001…
…0011100100000111011101
31120112011210112201001010111
42232301200103210013131
53033234141120113041
641313250452210021
72346501346064353
oct256614023440735
946464715631114
1012010344301021
113910616281310
12141b828009911
13691755819271
142d74377677d3
1515c63b13d981
hexaec604e41dd

12010344301021 has 4 divisors (see below), whose sum is σ = 13102193782944. Its totient is φ = 10918494819100.

The previous prime is 12010344300979. The next prime is 12010344301031.

12010344301021 is nontrivially palindromic in base 10.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 12010344301021 - 219 = 12010343776733 is a prime.

It is a super-2 number, since 2×120103443010212 (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12010344300983 and 12010344301001.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12010344301031) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 545924740945 + ... + 545924740966.

It is an arithmetic number, because the mean of its divisors is an integer number (3275548445736).

Almost surely, 212010344301021 is an apocalyptic number.

12010344301021 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

12010344301021 is a deficient number, since it is larger than the sum of its proper divisors (1091849481923).

12010344301021 is a wasteful number, since it uses less digits than its factorization.

12010344301021 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1091849481922.

The product of its (nonzero) digits is 576, while the sum is 22.

It can be divided in two parts, 1201034 and 4301021, that added together give a palindrome (5502055).

The spelling of 12010344301021 in words is "twelve trillion, ten billion, three hundred forty-four million, three hundred one thousand, twenty-one".

Divisors: 1 11 1091849481911 12010344301021