Base | Representation |
---|---|
bin | 11011010011110101001010… |
… | …100011010101110111010011 |
3 | 120202021101221012021121012212 |
4 | 123103311022203111313103 |
5 | 111220340300332224334 |
6 | 1103241435530542335 |
7 | 34204443022100321 |
oct | 3323651243256723 |
9 | 522241835247185 |
10 | 120110011211219 |
11 | 352a8408081497 |
12 | 1157a15b8979ab |
13 | 5203430050823 |
14 | 21934d9930d11 |
15 | dd450c714ece |
hex | 6d3d4a8d5dd3 |
120110011211219 has 2 divisors, whose sum is σ = 120110011211220. Its totient is φ = 120110011211218.
The previous prime is 120110011211149. The next prime is 120110011211233. The reversal of 120110011211219 is 912112110011021.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 120110011211219 - 244 = 102517825166803 is a prime.
It is a super-3 number, since 3×1201100112112193 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a junction number, because it is equal to n+sod(n) for n = 120110011211194 and 120110011211203.
It is not a weakly prime, because it can be changed into another prime (120110011211249) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60055005605609 + 60055005605610.
It is an arithmetic number, because the mean of its divisors is an integer number (60055005605610).
Almost surely, 2120110011211219 is an apocalyptic number.
120110011211219 is a deficient number, since it is larger than the sum of its proper divisors (1).
120110011211219 is an equidigital number, since it uses as much as digits as its factorization.
120110011211219 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 72, while the sum is 23.
The spelling of 120110011211219 in words is "one hundred twenty trillion, one hundred ten billion, eleven million, two hundred eleven thousand, two hundred nineteen".
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