Base | Representation |
---|---|
bin | 10110010111110100… |
… | …10101010100101101 |
3 | 1011000001211002001211 |
4 | 23023322111110231 |
5 | 144044304014013 |
6 | 5303501234421 |
7 | 603433553005 |
oct | 131372252455 |
9 | 34001732054 |
10 | 12011001133 |
11 | 5103995a1a |
12 | 23b2562a11 |
13 | 1195516c81 |
14 | 81d283005 |
15 | 4a46e523d |
hex | 2cbe9552d |
12011001133 has 2 divisors, whose sum is σ = 12011001134. Its totient is φ = 12011001132.
The previous prime is 12011001071. The next prime is 12011001157. The reversal of 12011001133 is 33110011021.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9273304804 + 2737696329 = 96298^2 + 52323^2 .
It is a cyclic number.
It is not a de Polignac number, because 12011001133 - 29 = 12011000621 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12011001173) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6005500566 + 6005500567.
It is an arithmetic number, because the mean of its divisors is an integer number (6005500567).
Almost surely, 212011001133 is an apocalyptic number.
It is an amenable number.
12011001133 is a deficient number, since it is larger than the sum of its proper divisors (1).
12011001133 is an equidigital number, since it uses as much as digits as its factorization.
12011001133 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 18, while the sum is 13.
Adding to 12011001133 its reverse (33110011021), we get a palindrome (45121012154).
The spelling of 12011001133 in words is "twelve billion, eleven million, one thousand, one hundred thirty-three".
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