Base | Representation |
---|---|
bin | 1010111011001000100101… |
… | …0000011000000111101110 |
3 | 1120112020120102110210111202 |
4 | 2232302021100120013232 |
5 | 3033242043010100220 |
6 | 41313442553445502 |
7 | 2346524360540204 |
oct | 256621120300756 |
9 | 46466512423452 |
10 | 12011031331310 |
11 | 3910939072340 |
12 | 141b99a110892 |
13 | 691834c6716b |
14 | 2d74a0ac7074 |
15 | 15c67b5ed275 |
hex | aec894181ee |
12011031331310 has 32 divisors (see below), whose sum is σ = 23585442233472. Its totient is φ = 4367621026080.
The previous prime is 12011031331309. The next prime is 12011031331361. The reversal of 12011031331310 is 1313313011021.
It is a super-4 number, since 4×120110313313104 (a number of 53 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 31112729 + ... + 31496411.
It is an arithmetic number, because the mean of its divisors is an integer number (737045069796).
Almost surely, 212011031331310 is an apocalyptic number.
12011031331310 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
12011031331310 is a deficient number, since it is larger than the sum of its proper divisors (11574410902162).
12011031331310 is a wasteful number, since it uses less digits than its factorization.
12011031331310 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 668288.
The product of its (nonzero) digits is 162, while the sum is 20.
Adding to 12011031331310 its reverse (1313313011021), we get a palindrome (13324344342331).
The spelling of 12011031331310 in words is "twelve trillion, eleven billion, thirty-one million, three hundred thirty-one thousand, three hundred ten".
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