Base | Representation |
---|---|
bin | 11011010011110110000110… |
… | …001101000011000110001111 |
3 | 120202021111111221102221112022 |
4 | 123103312012031003012033 |
5 | 111220344323033001033 |
6 | 1103242123121200355 |
7 | 34204506563465303 |
oct | 3323660615030617 |
9 | 522244457387468 |
10 | 120111012000143 |
11 | 352a8880a93a7a |
12 | 1157a39aa900bb |
13 | 520355c4a5b18 |
14 | 2193592805d03 |
15 | dd456a500098 |
hex | 6d3d8634318f |
120111012000143 has 2 divisors, whose sum is σ = 120111012000144. Its totient is φ = 120111012000142.
The previous prime is 120111012000113. The next prime is 120111012000233. The reversal of 120111012000143 is 341000210111021.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 120111012000143 - 212 = 120111011996047 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (120111012000113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60055506000071 + 60055506000072.
It is an arithmetic number, because the mean of its divisors is an integer number (60055506000072).
Almost surely, 2120111012000143 is an apocalyptic number.
120111012000143 is a deficient number, since it is larger than the sum of its proper divisors (1).
120111012000143 is an equidigital number, since it uses as much as digits as its factorization.
120111012000143 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 17.
Adding to 120111012000143 its reverse (341000210111021), we get a palindrome (461111222111164).
The spelling of 120111012000143 in words is "one hundred twenty trillion, one hundred eleven billion, twelve million, one hundred forty-three", and thus it is an aban number.
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