Base | Representation |
---|---|
bin | 10001011110100111110… |
… | …111011110001010011111 |
3 | 11020211021120112100012012 |
4 | 101132213313132022133 |
5 | 124134334211242002 |
6 | 2315441111101435 |
7 | 152530452231002 |
oct | 21364767361237 |
9 | 4224246470165 |
10 | 1201112212127 |
11 | 423430592573 |
12 | 17494a07187b |
13 | 89358b530a9 |
14 | 421c4125539 |
15 | 2139c684d52 |
hex | 117a7dde29f |
1201112212127 has 2 divisors, whose sum is σ = 1201112212128. Its totient is φ = 1201112212126.
The previous prime is 1201112212117. The next prime is 1201112212147. The reversal of 1201112212127 is 7212122111021.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1201112212127 - 214 = 1201112195743 is a prime.
It is a super-2 number, since 2×12011122121272 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1201112212117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600556106063 + 600556106064.
It is an arithmetic number, because the mean of its divisors is an integer number (600556106064).
Almost surely, 21201112212127 is an apocalyptic number.
1201112212127 is a deficient number, since it is larger than the sum of its proper divisors (1).
1201112212127 is an equidigital number, since it uses as much as digits as its factorization.
1201112212127 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 224, while the sum is 23.
Adding to 1201112212127 its reverse (7212122111021), we get a palindrome (8413234323148).
The spelling of 1201112212127 in words is "one trillion, two hundred one billion, one hundred twelve million, two hundred twelve thousand, one hundred twenty-seven".
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