1201120020001 has 4 divisors (see below), whose sum is σ = 1310312749104. Its totient is φ = 1091927290900.

The previous prime is 1201120019999. The next prime is 1201120020071. The reversal of 1201120020001 is 1000200211021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1201120020001 - 2¹ = 1201120019999 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1201120020001.

It is not an unprimeable number, because it can be changed into a prime (1201120020071) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 54596364535 + ... + 54596364556.

It is an arithmetic number, because the mean of its divisors is an integer number (327578187276).

Almost surely, 2^{1201120020001} is an apocalyptic number.

1201120020001 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

1201120020001 is a deficient number, since it is larger than the sum of its proper divisors (109192729103).

1201120020001 is a wasteful number, since it uses less digits than its factorization.

1201120020001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 109192729102.

The product of its (nonzero) digits is 8, while the sum is 10.

Adding to 1201120020001 its reverse (1000200211021), we get a palindrome (2201320231022).

The spelling of 1201120020001 in words is "one trillion, two hundred one billion, one hundred twenty million, twenty thousand, one".