Base | Representation |
---|---|
bin | 10001011110101000010… |
… | …101010000101010011111 |
3 | 11020211022010020002011022 |
4 | 101132220111100222133 |
5 | 124134343211134101 |
6 | 2315441550314355 |
7 | 152530605503561 |
oct | 21365025205237 |
9 | 4224263202138 |
10 | 1201120021151 |
11 | 423434a36606 |
12 | 1749507b89bb |
13 | 8935a65860b |
14 | 421c5199331 |
15 | 2139d1c8a1b |
hex | 117a8550a9f |
1201120021151 has 2 divisors, whose sum is σ = 1201120021152. Its totient is φ = 1201120021150.
The previous prime is 1201120021133. The next prime is 1201120021159. The reversal of 1201120021151 is 1511200211021.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1201120021151 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1201120021159) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600560010575 + 600560010576.
It is an arithmetic number, because the mean of its divisors is an integer number (600560010576).
Almost surely, 21201120021151 is an apocalyptic number.
1201120021151 is a deficient number, since it is larger than the sum of its proper divisors (1).
1201120021151 is an equidigital number, since it uses as much as digits as its factorization.
1201120021151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 40, while the sum is 17.
Adding to 1201120021151 its reverse (1511200211021), we get a palindrome (2712320232172).
The spelling of 1201120021151 in words is "one trillion, two hundred one billion, one hundred twenty million, twenty-one thousand, one hundred fifty-one".
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