Base | Representation |
---|---|
bin | 10001011110101000011… |
… | …101001100101011111101 |
3 | 11020211022021010210120021 |
4 | 101132220131030223331 |
5 | 124134344224231023 |
6 | 2315442103052141 |
7 | 152530632261331 |
oct | 21365035145375 |
9 | 4224267123507 |
10 | 1201122102013 |
11 | 423436127a29 |
12 | 174951441051 |
13 | 8935ac067b2 |
14 | 421c557b7c1 |
15 | 2139d48a35d |
hex | 117a874cafd |
1201122102013 has 2 divisors, whose sum is σ = 1201122102014. Its totient is φ = 1201122102012.
The previous prime is 1201122101983. The next prime is 1201122102023. The reversal of 1201122102013 is 3102012211021.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1028250756729 + 172871345284 = 1014027^2 + 415778^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1201122102013 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1201122102023) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600561051006 + 600561051007.
It is an arithmetic number, because the mean of its divisors is an integer number (600561051007).
Almost surely, 21201122102013 is an apocalyptic number.
It is an amenable number.
1201122102013 is a deficient number, since it is larger than the sum of its proper divisors (1).
1201122102013 is an equidigital number, since it uses as much as digits as its factorization.
1201122102013 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 48, while the sum is 16.
Adding to 1201122102013 its reverse (3102012211021), we get a palindrome (4303134313034).
The spelling of 1201122102013 in words is "one trillion, two hundred one billion, one hundred twenty-two million, one hundred two thousand, thirteen".
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