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1201122143303 = 11917310078811
BaseRepresentation
bin10001011110101000011…
…101010110110001000111
311020211022021012220012112
4101132220131112301013
5124134344232041203
62315442104011235
7152530632522605
oct21365035266107
94224267186175
101201122143303
11423436155a55
12174951460b1b
138935ac1c524
14421c558c875
152139d4976d8
hex117a8756c47

1201122143303 has 4 divisors (see below), whose sum is σ = 1201132341288. Its totient is φ = 1201111945320.

The previous prime is 1201122143267. The next prime is 1201122143317. The reversal of 1201122143303 is 3033412211021.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1201122143303 - 26 = 1201122143239 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1201122143363) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4920233 + ... + 5158578.

It is an arithmetic number, because the mean of its divisors is an integer number (300283085322).

Almost surely, 21201122143303 is an apocalyptic number.

1201122143303 is a deficient number, since it is larger than the sum of its proper divisors (10197985).

1201122143303 is a wasteful number, since it uses less digits than its factorization.

1201122143303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10197984.

The product of its (nonzero) digits is 864, while the sum is 23.

Adding to 1201122143303 its reverse (3033412211021), we get a palindrome (4234534354324).

The spelling of 1201122143303 in words is "one trillion, two hundred one billion, one hundred twenty-two million, one hundred forty-three thousand, three hundred three".

Divisors: 1 119173 10078811 1201122143303