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12011313111323 = 93187128894729
BaseRepresentation
bin1010111011001001101000…
…0011010010000100011011
31120112021022001200201000112
42232302122003102010123
53033243132124030243
641313530541154535
72346534351613241
oct256623203220433
946467261621015
1012011313111323
113910a73131889
12141ba5855ba4b
1369187b455ab6
142d74ca2b6791
1515c69620d818
hexaec9a0d211b

12011313111323 has 4 divisors (see below), whose sum is σ = 12011442099240. Its totient is φ = 12011184123408.

The previous prime is 12011313111319. The next prime is 12011313111341. The reversal of 12011313111323 is 32311131311021.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 12011313111323 - 22 = 12011313111319 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12011313111353) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 64354178 + ... + 64540551.

It is an arithmetic number, because the mean of its divisors is an integer number (3002860524810).

Almost surely, 212011313111323 is an apocalyptic number.

12011313111323 is a deficient number, since it is larger than the sum of its proper divisors (128987917).

12011313111323 is an equidigital number, since it uses as much as digits as its factorization.

12011313111323 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 128987916.

The product of its (nonzero) digits is 324, while the sum is 23.

Adding to 12011313111323 its reverse (32311131311021), we get a palindrome (44322444422344).

The spelling of 12011313111323 in words is "twelve trillion, eleven billion, three hundred thirteen million, one hundred eleven thousand, three hundred twenty-three".

Divisors: 1 93187 128894729 12011313111323