12011313130133 has 2 divisors, whose sum is σ = 12011313130134. Its totient is φ = 12011313130132.

The previous prime is 12011313130109. The next prime is 12011313130147. The reversal of 12011313130133 is 33103131311021.

12011313130133 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11655819339844 + 355493790289 = 3414062^2 + 596233^2 .

It is a cyclic number.

It is not a de Polignac number, because 12011313130133 - 2¹⁴ = 12011313113749 is a prime.

It is a super-2 number, since 2×12011313130133² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 12011313130099 and 12011313130108.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12011313130933) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6005656565066 + 6005656565067.

It is an arithmetic number, because the mean of its divisors is an integer number (6005656565067).

Almost surely, 2^{12011313130133} is an apocalyptic number.

It is an amenable number.

12011313130133 is a deficient number, since it is larger than the sum of its proper divisors (1).

12011313130133 is an equidigital number, since it uses as much as digits as its factorization.

12011313130133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 486, while the sum is 23.

Adding to 12011313130133 its reverse (33103131311021), we get a palindrome (45114444441154).

The spelling of 12011313130133 in words is "twelve trillion, eleven billion, three hundred thirteen million, one hundred thirty thousand, one hundred thirty-three".