Base | Representation |
---|---|
bin | 10001011110101001000… |
… | …010111101001111010101 |
3 | 11020211022221202200100021 |
4 | 101132221002331033111 |
5 | 124134404243001323 |
6 | 2315443055145141 |
7 | 152531112355135 |
oct | 21365102751725 |
9 | 4224287680307 |
10 | 1201132000213 |
11 | 423440778662 |
12 | 1749548151b1 |
13 | 8935cc90c12 |
14 | 421c69d6ac5 |
15 | 2139e29305d |
hex | 117a90bd3d5 |
1201132000213 has 4 divisors (see below), whose sum is σ = 1205564221888. Its totient is φ = 1196699778540.
The previous prime is 1201132000199. The next prime is 1201132000217. The reversal of 1201132000213 is 3120002311021.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1201132000213 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1201132000217) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2216110431 + ... + 2216110972.
It is an arithmetic number, because the mean of its divisors is an integer number (301391055472).
Almost surely, 21201132000213 is an apocalyptic number.
It is an amenable number.
1201132000213 is a deficient number, since it is larger than the sum of its proper divisors (4432221675).
1201132000213 is an equidigital number, since it uses as much as digits as its factorization.
1201132000213 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4432221674.
The product of its (nonzero) digits is 72, while the sum is 16.
Adding to 1201132000213 its reverse (3120002311021), we get a palindrome (4321134311234).
The spelling of 1201132000213 in words is "one trillion, two hundred one billion, one hundred thirty-two million, two hundred thirteen", and thus it is an aban number.
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