Base | Representation |
---|---|
bin | 10110010111110111… |
… | …01000001001010101 |
3 | 1011000002110022102021 |
4 | 23023323220021111 |
5 | 144044400342443 |
6 | 5303512413141 |
7 | 603436465024 |
oct | 131373501125 |
9 | 34002408367 |
10 | 12011340373 |
11 | 51040a788a |
12 | 23b26a71b1 |
13 | 11956054c6 |
14 | 81d3308bb |
15 | 4a47609ed |
hex | 2cbee8255 |
12011340373 has 2 divisors, whose sum is σ = 12011340374. Its totient is φ = 12011340372.
The previous prime is 12011340317. The next prime is 12011340431. The reversal of 12011340373 is 37304311021.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 11046430404 + 964909969 = 105102^2 + 31063^2 .
It is an emirp because it is prime and its reverse (37304311021) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12011340373 - 29 = 12011339861 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12011341373) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6005670186 + 6005670187.
It is an arithmetic number, because the mean of its divisors is an integer number (6005670187).
Almost surely, 212011340373 is an apocalyptic number.
It is an amenable number.
12011340373 is a deficient number, since it is larger than the sum of its proper divisors (1).
12011340373 is an equidigital number, since it uses as much as digits as its factorization.
12011340373 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1512, while the sum is 25.
Adding to 12011340373 its reverse (37304311021), we get a palindrome (49315651394).
The spelling of 12011340373 in words is "twelve billion, eleven million, three hundred forty thousand, three hundred seventy-three".
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