Base | Representation |
---|---|
bin | 10110010111110111… |
… | …01000001000011101 |
3 | 1011000002110022100012 |
4 | 23023323220020131 |
5 | 144044400342232 |
6 | 5303512413005 |
7 | 603436464614 |
oct | 131373501035 |
9 | 34002408305 |
10 | 12011340317 |
11 | 51040a7839 |
12 | 23b26a7165 |
13 | 1195605482 |
14 | 81d33087b |
15 | 4a47609b2 |
hex | 2cbee821d |
12011340317 has 2 divisors, whose sum is σ = 12011340318. Its totient is φ = 12011340316.
The previous prime is 12011340287. The next prime is 12011340373. The reversal of 12011340317 is 71304311021.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 8451308761 + 3560031556 = 91931^2 + 59666^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12011340317 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 12011340292 and 12011340301.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12011345317) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6005670158 + 6005670159.
It is an arithmetic number, because the mean of its divisors is an integer number (6005670159).
Almost surely, 212011340317 is an apocalyptic number.
It is an amenable number.
12011340317 is a deficient number, since it is larger than the sum of its proper divisors (1).
12011340317 is an equidigital number, since it uses as much as digits as its factorization.
12011340317 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 504, while the sum is 23.
Adding to 12011340317 its reverse (71304311021), we get a palindrome (83315651338).
The spelling of 12011340317 in words is "twelve billion, eleven million, three hundred forty thousand, three hundred seventeen".
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