120114013 has 4 divisors (see below), whose sum is σ = 120138940. Its totient is φ = 120089088.

The previous prime is 120113977. The next prime is 120114047. The reversal of 120114013 is 310411021.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 310411021 = 3511 ⋅88411.

It can be written as a sum of positive squares in 2 ways, for example, as 59320804 + 60793209 = 7702^2 + 7797^2 .

It is a cyclic number.

It is not a de Polignac number, because 120114013 - 2²⁵ = 86559581 is a prime.

It is a super-2 number, since 2×120114013² = 28854752237928338, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 120113984 and 120114002.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (120114083) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2670 + ... + 15727.

It is an arithmetic number, because the mean of its divisors is an integer number (30034735).

Almost surely, 2^120114013 is an apocalyptic number.

It is an amenable number.

120114013 is a deficient number, since it is larger than the sum of its proper divisors (24927).

120114013 is an equidigital number, since it uses as much as digits as its factorization.

120114013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 24926.

The product of its (nonzero) digits is 24, while the sum is 13.

The square root of 120114013 is about 10959.6538722717. The cubic root of 120114013 is about 493.3985766626.

Adding to 120114013 its reverse (310411021), we get a palindrome (430525034).

The spelling of 120114013 in words is "one hundred twenty million, one hundred fourteen thousand, thirteen".