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120120313002002 = 287768483644813
BaseRepresentation
bin11011010011111110110000…
…100101100011100000010010
3120202022101112010220210110122
4123103332300211203200102
5111221022400112031002
61103250302054030242
734205256222630635
oct3323766045434022
9522271463823418
10120120313002002
1135301814183375
1211580155948382
1352043b2414c11
142193bd5bb1c1c
15dd4911d376a2
hex6d3fb0963812

120120313002002 has 8 divisors (see below), whose sum is σ = 180385920440076. Its totient is φ = 59991672855312.

The previous prime is 120120313001999. The next prime is 120120313002047. The reversal of 120120313002002 is 200200313021021.

It can be written as a sum of positive squares in 2 ways, for example, as 93922284205201 + 26198028796801 = 9691351^2 + 5118401^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 34241820653 + ... + 34241824160.

Almost surely, 2120120313002002 is an apocalyptic number.

120120313002002 is a deficient number, since it is larger than the sum of its proper divisors (60265607438074).

120120313002002 is an equidigital number, since it uses as much as digits as its factorization.

120120313002002 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 68483645692.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 120120313002002 its reverse (200200313021021), we get a palindrome (320320626023023).

The spelling of 120120313002002 in words is "one hundred twenty trillion, one hundred twenty billion, three hundred thirteen million, two thousand, two".

Divisors: 1 2 877 1754 68483644813 136967289626 60060156501001 120120313002002