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12012102011113 = 231173144520101
BaseRepresentation
bin1010111011001100100100…
…0100101100100011101001
31120112100100001010222002021
42232303021010230203221
53033301241103323423
641314141122104441
72346563041265521
oct256631104544351
946470301128067
1012012102011113
113911338480986
1214200387ab121
13691975a203c9
142d7562d92681
1515c6e05e195d
hexaecc912c8e9

12012102011113 has 8 divisors (see below), whose sum is σ = 12535436079936. Its totient is φ = 11488857006000.

The previous prime is 12012102011101. The next prime is 12012102011177. The reversal of 12012102011113 is 31111020121021.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a de Polignac number, because none of the positive numbers 2k-12012102011113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12012102011513) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 21990238 + ... + 22529863.

It is an arithmetic number, because the mean of its divisors is an integer number (1566929509992).

Almost surely, 212012102011113 is an apocalyptic number.

It is an amenable number.

12012102011113 is a deficient number, since it is larger than the sum of its proper divisors (523334068823).

12012102011113 is a wasteful number, since it uses less digits than its factorization.

12012102011113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 44531855.

The product of its (nonzero) digits is 24, while the sum is 16.

Adding to 12012102011113 its reverse (31111020121021), we get a palindrome (43123122132134).

The spelling of 12012102011113 in words is "twelve trillion, twelve billion, one hundred two million, eleven thousand, one hundred thirteen".

Divisors: 1 23 11731 269813 44520101 1023962323 522265304831 12012102011113