Base | Representation |
---|---|
bin | 10110010111111101… |
… | …00010000111111111 |
3 | 1011000010220000100222 |
4 | 23023332202013333 |
5 | 144100044232033 |
6 | 5303541011555 |
7 | 603446116646 |
oct | 131376420777 |
9 | 34003800328 |
10 | 12012102143 |
11 | 5104578148 |
12 | 23b29b3bbb |
13 | 1195811162 |
14 | 81d48c35d |
15 | 4a4861598 |
hex | 2cbfa21ff |
12012102143 has 2 divisors, whose sum is σ = 12012102144. Its totient is φ = 12012102142.
The previous prime is 12012102101. The next prime is 12012102149. The reversal of 12012102143 is 34120121021.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12012102143 - 26 = 12012102079 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12012102149) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6006051071 + 6006051072.
It is an arithmetic number, because the mean of its divisors is an integer number (6006051072).
Almost surely, 212012102143 is an apocalyptic number.
12012102143 is a deficient number, since it is larger than the sum of its proper divisors (1).
12012102143 is an equidigital number, since it uses as much as digits as its factorization.
12012102143 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 96, while the sum is 17.
Adding to 12012102143 its reverse (34120121021), we get a palindrome (46132223164).
The spelling of 12012102143 in words is "twelve billion, twelve million, one hundred two thousand, one hundred forty-three".
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