12012103 has 4 divisors (see below), whose sum is σ = 12020008. Its totient is φ = 12004200.

The previous prime is 12012101. The next prime is 12012109. The reversal of 12012103 is 30121021.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 12012103 - 2¹ = 12012101 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 12012103.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12012101) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 873 + ... + 4978.

It is an arithmetic number, because the mean of its divisors is an integer number (3005002).

Almost surely, 2^12012103 is an apocalyptic number.

12012103 is a deficient number, since it is larger than the sum of its proper divisors (7905).

12012103 is an equidigital number, since it uses as much as digits as its factorization.

12012103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7904.

The product of its (nonzero) digits is 12, while the sum is 10.

The square root of 12012103 is about 3465.8480924588. The cubic root of 12012103 is about 229.0197919623.

Adding to 12012103 its reverse (30121021), we get a palindrome (42133124).

The spelling of 12012103 in words is "twelve million, twelve thousand, one hundred three".