12012113 has 2 divisors, whose sum is σ = 12012114. Its totient is φ = 12012112.

The previous prime is 12012109. The next prime is 12012131. The reversal of 12012113 is 31121021.

12012113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

Together with next prime (12012131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 6385729 + 5626384 = 2527^2 + 2372^2 .

It is an emirp because it is prime and its reverse (31121021) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12012113 - 2² = 12012109 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 12012094 and 12012103.

It is not a weakly prime, because it can be changed into another prime (12012173) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6006056 + 6006057.

It is an arithmetic number, because the mean of its divisors is an integer number (6006057).

Almost surely, 2^12012113 is an apocalyptic number.

It is an amenable number.

12012113 is a deficient number, since it is larger than the sum of its proper divisors (1).

12012113 is an equidigital number, since it uses as much as digits as its factorization.

12012113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12, while the sum is 11.

The square root of 12012113 is about 3465.8495351068. The cubic root of 12012113 is about 229.0198555148.

Adding to 12012113 its reverse (31121021), we get a palindrome (43133134).

The spelling of 12012113 in words is "twelve million, twelve thousand, one hundred thirteen".