12012120003113 has 4 divisors (see below), whose sum is σ = 12012165893520. Its totient is φ = 12012074112708.

The previous prime is 12012120003077. The next prime is 12012120003157. The reversal of 12012120003113 is 31130002121021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12012120003113 - 2¹⁶ = 12012119937577 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12012120003091 and 12012120003100.

It is not an unprimeable number, because it can be changed into a prime (12012120003173) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22550303 + ... + 23076836.

It is an arithmetic number, because the mean of its divisors is an integer number (3003041473380).

Almost surely, 2^{12012120003113} is an apocalyptic number.

It is an amenable number.

12012120003113 is a deficient number, since it is larger than the sum of its proper divisors (45890407).

12012120003113 is an equidigital number, since it uses as much as digits as its factorization.

12012120003113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 45890406.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 12012120003113 its reverse (31130002121021), we get a palindrome (43142122124134).

The spelling of 12012120003113 in words is "twelve trillion, twelve billion, one hundred twenty million, three thousand, one hundred thirteen".