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1201213103 = 3732465219
BaseRepresentation
bin100011110011001…
…0000111010101111
310002201021221121012
41013212100322233
54430002304403
6315110055435
741524100006
oct10746207257
93081257535
101201213103
11567065202
1229634a57b
13161b2a6ac
14b5767c3d
15706c9ed8
hex47990eaf

1201213103 has 4 divisors (see below), whose sum is σ = 1233678360. Its totient is φ = 1168747848.

The previous prime is 1201213061. The next prime is 1201213109. The reversal of 1201213103 is 3013121021.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1201213103 - 210 = 1201212079 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1201213109) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16232573 + ... + 16232646.

It is an arithmetic number, because the mean of its divisors is an integer number (308419590).

Almost surely, 21201213103 is an apocalyptic number.

1201213103 is a deficient number, since it is larger than the sum of its proper divisors (32465257).

1201213103 is an equidigital number, since it uses as much as digits as its factorization.

1201213103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 32465256.

The product of its (nonzero) digits is 36, while the sum is 14.

The square root of 1201213103 is about 34658.5213619970. The cubic root of 1201213103 is about 1063.0165358896.

Adding to 1201213103 its reverse (3013121021), we get a palindrome (4214334124).

The spelling of 1201213103 in words is "one billion, two hundred one million, two hundred thirteen thousand, one hundred three".

Divisors: 1 37 32465219 1201213103