12012133000130 has 8 divisors (see below), whose sum is σ = 21621839400252. Its totient is φ = 4804853200048.

The previous prime is 12012133000111. The next prime is 12012133000187. The reversal of 12012133000130 is 3100033121021.

It can be written as a sum of positive squares in 2 ways, for example, as 9772144837849 + 2239988162281 = 3126043^2 + 1496659^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 12012133000099 and 12012133000108.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 600606649997 + ... + 600606650016.

Almost surely, 2^{12012133000130} is an apocalyptic number.

12012133000130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

12012133000130 is a deficient number, since it is larger than the sum of its proper divisors (9609706400122).

12012133000130 is a wasteful number, since it uses less digits than its factorization.

12012133000130 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1201213300020.

The product of its (nonzero) digits is 108, while the sum is 17.

Adding to 12012133000130 its reverse (3100033121021), we get a palindrome (15112166121151).

The spelling of 12012133000130 in words is "twelve trillion, twelve billion, one hundred thirty-three million, one hundred thirty", and thus it is an aban number.