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12012141433135 = 519669118897563
BaseRepresentation
bin1010111011001100101101…
…1011000101000100101111
31120112100102210022210221011
42232303023123011010233
53033301331201330020
641314145051050051
72346564030335524
oct256631333050457
946470383283834
1012012141433135
113911358757268
121420049a40927
13691980c43b4c
142d75682d514b
1515c6e3ccc35a
hexaeccb6c512f

12012141433135 has 16 divisors (see below), whose sum is σ = 15175499794560. Its totient is φ = 9102577664160.

The previous prime is 12012141433133. The next prime is 12012141433157. The reversal of 12012141433135 is 53133414121021.

It is a happy number.

It is not a de Polignac number, because 12012141433135 - 21 = 12012141433133 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 12012141433097 and 12012141433106.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12012141433133) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 8813137 + ... + 10084426.

It is an arithmetic number, because the mean of its divisors is an integer number (948468737160).

Almost surely, 212012141433135 is an apocalyptic number.

12012141433135 is a deficient number, since it is larger than the sum of its proper divisors (3163358361425).

12012141433135 is a wasteful number, since it uses less digits than its factorization.

12012141433135 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 18904278.

The product of its (nonzero) digits is 8640, while the sum is 31.

Adding to 12012141433135 its reverse (53133414121021), we get a palindrome (65145555554156).

The spelling of 12012141433135 in words is "twelve trillion, twelve billion, one hundred forty-one million, four hundred thirty-three thousand, one hundred thirty-five".

Divisors: 1 5 19 95 6691 33455 127129 635645 18897563 94487815 359053697 1795268485 126443594033 632217970165 2402428286627 12012141433135