Base | Representation |
---|---|
bin | 11011010011111111110100… |
… | …101011000101100110001111 |
3 | 120202022111110202100200221001 |
4 | 123103333310223011212033 |
5 | 111221032220024144210 |
6 | 1103251011301321131 |
7 | 34205326433214463 |
oct | 3323776453054617 |
9 | 522274422320831 |
10 | 120121455303055 |
11 | 3530224aa60028 |
12 | 115804144061a7 |
13 | 5204534c868bb |
14 | 2193ca37a24a3 |
15 | dd497c27703a |
hex | 6d3ff4ac598f |
120121455303055 has 4 divisors (see below), whose sum is σ = 144145746363672. Its totient is φ = 96097164242440.
The previous prime is 120121455303053. The next prime is 120121455303061. The reversal of 120121455303055 is 550303554121021.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 120121455303055 - 21 = 120121455303053 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (120121455303053) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12012145530301 + ... + 12012145530310.
It is an arithmetic number, because the mean of its divisors is an integer number (36036436590918).
Almost surely, 2120121455303055 is an apocalyptic number.
120121455303055 is a deficient number, since it is larger than the sum of its proper divisors (24024291060617).
120121455303055 is an equidigital number, since it uses as much as digits as its factorization.
120121455303055 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 24024291060616.
The product of its (nonzero) digits is 90000, while the sum is 37.
The spelling of 120121455303055 in words is "one hundred twenty trillion, one hundred twenty-one billion, four hundred fifty-five million, three hundred three thousand, fifty-five".
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