Base | Representation |
---|---|
bin | 11011010100000000010101… |
… | …010000111111111100000111 |
3 | 120202022112212212021111010221 |
4 | 123110000111100333330013 |
5 | 111221034330020043023 |
6 | 1103251141433325211 |
7 | 34205346123056434 |
oct | 3324002520777407 |
9 | 522275785244127 |
10 | 120122002112263 |
11 | 35302500688968 |
12 | 11580547566807 |
13 | 52045c134a948 |
14 | 2193d16260b8b |
15 | dd49b028985d |
hex | 6d401543ff07 |
120122002112263 has 2 divisors, whose sum is σ = 120122002112264. Its totient is φ = 120122002112262.
The previous prime is 120122002112197. The next prime is 120122002112303. The reversal of 120122002112263 is 362211200221021.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 120122002112263 - 245 = 84937630023431 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (120122002112663) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60061001056131 + 60061001056132.
It is an arithmetic number, because the mean of its divisors is an integer number (60061001056132).
Almost surely, 2120122002112263 is an apocalyptic number.
120122002112263 is a deficient number, since it is larger than the sum of its proper divisors (1).
120122002112263 is an equidigital number, since it uses as much as digits as its factorization.
120122002112263 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 120122002112263 its reverse (362211200221021), we get a palindrome (482333202333284).
The spelling of 120122002112263 in words is "one hundred twenty trillion, one hundred twenty-two billion, two million, one hundred twelve thousand, two hundred sixty-three".
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