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1201220114951 is a prime number
BaseRepresentation
bin10001011110101110010…
…011000101101000000111
311020211120002120101001002
4101132232103011220013
5124140044322134301
62315455523523515
7152533232336333
oct21365623055007
94224502511032
101201220114951
1142348649155a
1217497a22959b
1389375302a0c
14421d45b27c3
15213a6d9b16b
hex117ae4c5a07

1201220114951 has 2 divisors, whose sum is σ = 1201220114952. Its totient is φ = 1201220114950.

The previous prime is 1201220114933. The next prime is 1201220114959. The reversal of 1201220114951 is 1594110221021.

It is a happy number.

It is a strong prime.

It is an emirp because it is prime and its reverse (1594110221021) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1201220114951 - 210 = 1201220113927 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1201220114959) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600610057475 + 600610057476.

It is an arithmetic number, because the mean of its divisors is an integer number (600610057476).

Almost surely, 21201220114951 is an apocalyptic number.

1201220114951 is a deficient number, since it is larger than the sum of its proper divisors (1).

1201220114951 is an equidigital number, since it uses as much as digits as its factorization.

1201220114951 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1440, while the sum is 29.

Adding to 1201220114951 its reverse (1594110221021), we get a palindrome (2795330335972).

The spelling of 1201220114951 in words is "one trillion, two hundred one billion, two hundred twenty million, one hundred fourteen thousand, nine hundred fifty-one".