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1201220200111 is a prime number
BaseRepresentation
bin10001011110101110010…
…011011010011010101111
311020211120002201200212011
4101132232103122122233
5124140044332400421
62315455525422051
7152533233142531
oct21365623323257
94224502650764
101201220200111
1142348653a538
1217497a26a927
13893753326c9
14421d45d5851
15213a6db64e1
hex117ae4da6af

1201220200111 has 2 divisors, whose sum is σ = 1201220200112. Its totient is φ = 1201220200110.

The previous prime is 1201220200079. The next prime is 1201220200151. The reversal of 1201220200111 is 1110020221021.

It is a weak prime.

It is an emirp because it is prime and its reverse (1110020221021) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1201220200111 - 25 = 1201220200079 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1201220200091 and 1201220200100.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1201220200151) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600610100055 + 600610100056.

It is an arithmetic number, because the mean of its divisors is an integer number (600610100056).

Almost surely, 21201220200111 is an apocalyptic number.

1201220200111 is a deficient number, since it is larger than the sum of its proper divisors (1).

1201220200111 is an equidigital number, since it uses as much as digits as its factorization.

1201220200111 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 16, while the sum is 13.

Adding to 1201220200111 its reverse (1110020221021), we get a palindrome (2311240421132).

The spelling of 1201220200111 in words is "one trillion, two hundred one billion, two hundred twenty million, two hundred thousand, one hundred eleven".