Base | Representation |
---|---|
bin | 1010111011001100111100… |
… | …0010001000011001100111 |
3 | 1120112100121000022000211022 |
4 | 2232303033002020121213 |
5 | 3033301442203031043 |
6 | 41314155053201355 |
7 | 2346565364222306 |
oct | 256631702103147 |
9 | 46470530260738 |
10 | 12012202002023 |
11 | 39113899665a3 |
12 | 142006619025b |
13 | 69199065ca22 |
14 | 2d757238043d |
15 | 15c6e9293868 |
hex | aeccf088667 |
12012202002023 has 2 divisors, whose sum is σ = 12012202002024. Its totient is φ = 12012202002022.
The previous prime is 12012202002001. The next prime is 12012202002041. The reversal of 12012202002023 is 32020020221021.
12012202002023 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12012202002023 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 12012202001992 and 12012202002010.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12012202002083) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6006101001011 + 6006101001012.
It is an arithmetic number, because the mean of its divisors is an integer number (6006101001012).
Almost surely, 212012202002023 is an apocalyptic number.
12012202002023 is a deficient number, since it is larger than the sum of its proper divisors (1).
12012202002023 is an equidigital number, since it uses as much as digits as its factorization.
12012202002023 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 192, while the sum is 17.
Adding to 12012202002023 its reverse (32020020221021), we get a palindrome (44032222223044).
The spelling of 12012202002023 in words is "twelve trillion, twelve billion, two hundred two million, two thousand, twenty-three".
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