Base | Representation |
---|---|
bin | 110111111011111010… |
… | …1001001100011110101 |
3 | 102111001111202222101201 |
4 | 1233313311021203311 |
5 | 3432002214202013 |
6 | 131103331452501 |
7 | 11451510225031 |
oct | 1576765114365 |
9 | 374044688351 |
10 | 120122022133 |
11 | 46a41828163 |
12 | 1b344757131 |
13 | b43456b809 |
14 | 5b5762b1c1 |
15 | 31d0a5a3dd |
hex | 1bf7d498f5 |
120122022133 has 2 divisors, whose sum is σ = 120122022134. Its totient is φ = 120122022132.
The previous prime is 120122022077. The next prime is 120122022187. The reversal of 120122022133 is 331220221021.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 111357692209 + 8764329924 = 333703^2 + 93618^2 .
It is a cyclic number.
It is not a de Polignac number, because 120122022133 - 229 = 119585151221 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 120122022133.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (120122029133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60061011066 + 60061011067.
It is an arithmetic number, because the mean of its divisors is an integer number (60061011067).
Almost surely, 2120122022133 is an apocalyptic number.
It is an amenable number.
120122022133 is a deficient number, since it is larger than the sum of its proper divisors (1).
120122022133 is an equidigital number, since it uses as much as digits as its factorization.
120122022133 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 288, while the sum is 19.
Adding to 120122022133 its reverse (331220221021), we get a palindrome (451342243154).
The spelling of 120122022133 in words is "one hundred twenty billion, one hundred twenty-two million, twenty-two thousand, one hundred thirty-three".
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