Base | Representation |
---|---|
bin | 10110010111111101… |
… | …11100101111001011 |
3 | 1011000011002112220011 |
4 | 23023332330233023 |
5 | 144100111224042 |
6 | 5303543212351 |
7 | 603450052516 |
oct | 131376745713 |
9 | 34004075804 |
10 | 12012211147 |
11 | 5104642032 |
12 | 23b2a470b7 |
13 | 119584b961 |
14 | 81d4b9d7d |
15 | 4a4883a17 |
hex | 2cbfbcbcb |
12012211147 has 2 divisors, whose sum is σ = 12012211148. Its totient is φ = 12012211146.
The previous prime is 12012211069. The next prime is 12012211151. The reversal of 12012211147 is 74111221021.
It is a happy number.
It is a strong prime.
It is an emirp because it is prime and its reverse (74111221021) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12012211147 - 215 = 12012178379 is a prime.
It is a super-2 number, since 2×120122111472 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (12012211847) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6006105573 + 6006105574.
It is an arithmetic number, because the mean of its divisors is an integer number (6006105574).
Almost surely, 212012211147 is an apocalyptic number.
12012211147 is a deficient number, since it is larger than the sum of its proper divisors (1).
12012211147 is an equidigital number, since it uses as much as digits as its factorization.
12012211147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 224, while the sum is 22.
Adding to 12012211147 its reverse (74111221021), we get a palindrome (86123432168).
The spelling of 12012211147 in words is "twelve billion, twelve million, two hundred eleven thousand, one hundred forty-seven".
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