Base | Representation |
---|---|
bin | 10110010111111101… |
… | …11100111100101011 |
3 | 1011000011002121002011 |
4 | 23023332330330223 |
5 | 144100111241021 |
6 | 5303543220351 |
7 | 603450055162 |
oct | 131376747453 |
9 | 34004077064 |
10 | 12012212011 |
11 | 5104642748 |
12 | 23b2a476b7 |
13 | 119584c177 |
14 | 81d4ba3d9 |
15 | 4a4883de1 |
hex | 2cbfbcf2b |
12012212011 has 2 divisors, whose sum is σ = 12012212012. Its totient is φ = 12012212010.
The previous prime is 12012211997. The next prime is 12012212027. The reversal of 12012212011 is 11021221021.
It is a weak prime.
It is an emirp because it is prime and its reverse (11021221021) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12012212011 - 29 = 12012211499 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 12012211982 and 12012212000.
It is not a weakly prime, because it can be changed into another prime (12012212111) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6006106005 + 6006106006.
It is an arithmetic number, because the mean of its divisors is an integer number (6006106006).
Almost surely, 212012212011 is an apocalyptic number.
12012212011 is a deficient number, since it is larger than the sum of its proper divisors (1).
12012212011 is an equidigital number, since it uses as much as digits as its factorization.
12012212011 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 16, while the sum is 13.
Adding to 12012212011 its reverse (11021221021), we get a palindrome (23033433032).
The spelling of 12012212011 in words is "twelve billion, twelve million, two hundred twelve thousand, eleven".
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