Base | Representation |
---|---|
bin | 10001011110101110010… |
… | …111001110110011100010 |
3 | 11020211120011121112222122 |
4 | 101132232113032303202 |
5 | 124140100111413442 |
6 | 2315500003104242 |
7 | 152533244512115 |
oct | 21365627166342 |
9 | 4224504545878 |
10 | 1201221201122 |
11 | 423487063618 |
12 | 17497a672082 |
13 | 893755c3217 |
14 | 421d47b657c |
15 | 213a7012dd2 |
hex | 117ae5cece2 |
1201221201122 has 4 divisors (see below), whose sum is σ = 1801831801686. Its totient is φ = 600610600560.
The previous prime is 1201221201109. The next prime is 1201221201127. The reversal of 1201221201122 is 2211021221021.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 769428963241 + 431792237881 = 877171^2 + 657109^2 .
It is a self number, because there is not a number n which added to its sum of digits gives 1201221201122.
It is not an unprimeable number, because it can be changed into a prime (1201221201127) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 300305300279 + ... + 300305300282.
Almost surely, 21201221201122 is an apocalyptic number.
1201221201122 is a deficient number, since it is larger than the sum of its proper divisors (600610600564).
1201221201122 is an equidigital number, since it uses as much as digits as its factorization.
1201221201122 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 600610600563.
The product of its (nonzero) digits is 64, while the sum is 17.
Adding to 1201221201122 its reverse (2211021221021), we get a palindrome (3412242422143).
The spelling of 1201221201122 in words is "one trillion, two hundred one billion, two hundred twenty-one million, two hundred one thousand, one hundred twenty-two".
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