Base | Representation |
---|---|
bin | 10001011110101110011… |
… | …010101100101110100001 |
3 | 11020211120020022201212222 |
4 | 101132232122230232201 |
5 | 124140100330010423 |
6 | 2315500034400425 |
7 | 152533255316204 |
oct | 21365632545641 |
9 | 4224506281788 |
10 | 1201222110113 |
11 | 423487624553 |
12 | 17497aa30115 |
13 | 89375850b9c |
14 | 421d497193b |
15 | 213a71423c8 |
hex | 117ae6acba1 |
1201222110113 has 2 divisors, whose sum is σ = 1201222110114. Its totient is φ = 1201222110112.
The previous prime is 1201222110083. The next prime is 1201222110161. The reversal of 1201222110113 is 3110112221021.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 947540655889 + 253681454224 = 973417^2 + 503668^2 .
It is a cyclic number.
It is not a de Polignac number, because 1201222110113 - 222 = 1201217915809 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1201222110091 and 1201222110100.
It is not a weakly prime, because it can be changed into another prime (1201222110163) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600611055056 + 600611055057.
It is an arithmetic number, because the mean of its divisors is an integer number (600611055057).
Almost surely, 21201222110113 is an apocalyptic number.
It is an amenable number.
1201222110113 is a deficient number, since it is larger than the sum of its proper divisors (1).
1201222110113 is an equidigital number, since it uses as much as digits as its factorization.
1201222110113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 17.
Adding to 1201222110113 its reverse (3110112221021), we get a palindrome (4311334331134).
The spelling of 1201222110113 in words is "one trillion, two hundred one billion, two hundred twenty-two million, one hundred ten thousand, one hundred thirteen".
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