Base | Representation |
---|---|
bin | 110111111011111011… |
… | …0010010100010010111 |
3 | 102111001112100011102121 |
4 | 1233313312102202113 |
5 | 3432002303233142 |
6 | 131103342120411 |
7 | 11451512611351 |
oct | 1576766224227 |
9 | 374045304377 |
10 | 120122321047 |
11 | 46a41a117a3 |
12 | 1b344880107 |
13 | b4346448a1 |
14 | 5b576a80d1 |
15 | 31d0ab8c67 |
hex | 1bf7d92897 |
120122321047 has 2 divisors, whose sum is σ = 120122321048. Its totient is φ = 120122321046.
The previous prime is 120122321017. The next prime is 120122321051. The reversal of 120122321047 is 740123221021.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 120122321047 - 219 = 120121796759 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (120122321017) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60061160523 + 60061160524.
It is an arithmetic number, because the mean of its divisors is an integer number (60061160524).
Almost surely, 2120122321047 is an apocalyptic number.
120122321047 is a deficient number, since it is larger than the sum of its proper divisors (1).
120122321047 is an equidigital number, since it uses as much as digits as its factorization.
120122321047 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1344, while the sum is 25.
Adding to 120122321047 its reverse (740123221021), we get a palindrome (860245542068).
The spelling of 120122321047 in words is "one hundred twenty billion, one hundred twenty-two million, three hundred twenty-one thousand, forty-seven".
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