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12012300031 = 47459253109
BaseRepresentation
bin10110010111111110…
…10010011011111111
31011000011021001211011
423023333102123333
5144100122100111
65303545140051
7603450602614
oct131377223377
934004231734
1012012300031
1151046a2896
1223b2a8a627
131195880254
1481d50050b
154a48a0021
hex2cbfd26ff

12012300031 has 4 divisors (see below), whose sum is σ = 12012600600. Its totient is φ = 12011999464.

The previous prime is 12012300029. The next prime is 12012300059. The reversal of 12012300031 is 13000321021.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 12012300031 - 21 = 12012300029 is a prime.

It is a super-2 number, since 2×120123000312 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12012299984 and 12012300020.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12012300731) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 79096 + ... + 174013.

It is an arithmetic number, because the mean of its divisors is an integer number (3003150150).

Almost surely, 212012300031 is an apocalyptic number.

12012300031 is a deficient number, since it is larger than the sum of its proper divisors (300569).

12012300031 is an equidigital number, since it uses as much as digits as its factorization.

12012300031 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 300568.

The product of its (nonzero) digits is 36, while the sum is 13.

Adding to 12012300031 its reverse (13000321021), we get a palindrome (25012621052).

The spelling of 12012300031 in words is "twelve billion, twelve million, three hundred thousand, thirty-one".

Divisors: 1 47459 253109 12012300031