Base | Representation |
---|---|
bin | 110111111011111100… |
… | …1010011101100100111 |
3 | 102111001120211100201201 |
4 | 1233313321103230213 |
5 | 3432003004042411 |
6 | 131103411103331 |
7 | 11451522415123 |
oct | 1576771235447 |
9 | 374046740651 |
10 | 120123112231 |
11 | 46a42402171 |
12 | 1b344ba1b47 |
13 | b434860a45 |
14 | 5b57832583 |
15 | 31d0bc33c1 |
hex | 1bf7e53b27 |
120123112231 has 2 divisors, whose sum is σ = 120123112232. Its totient is φ = 120123112230.
The previous prime is 120123112229. The next prime is 120123112247. The reversal of 120123112231 is 132211321021.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 120123112231 - 21 = 120123112229 is a prime.
It is a super-2 number, since 2×1201231122312 (a number of 23 digits) contains 22 as substring.
Together with 120123112229, it forms a pair of twin primes.
It is a junction number, because it is equal to n+sod(n) for n = 120123112199 and 120123112208.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (120123112211) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60061556115 + 60061556116.
It is an arithmetic number, because the mean of its divisors is an integer number (60061556116).
Almost surely, 2120123112231 is an apocalyptic number.
120123112231 is a deficient number, since it is larger than the sum of its proper divisors (1).
120123112231 is an equidigital number, since it uses as much as digits as its factorization.
120123112231 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 120123112231 its reverse (132211321021), we get a palindrome (252334433252).
The spelling of 120123112231 in words is "one hundred twenty billion, one hundred twenty-three million, one hundred twelve thousand, two hundred thirty-one".
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