Base | Representation |
---|---|
bin | 110111111011111111… |
… | …0010110000000100111 |
3 | 102111001200022102200201 |
4 | 1233313332112000213 |
5 | 3432003323314143 |
6 | 131103455251331 |
7 | 11451536554102 |
oct | 1576776260047 |
9 | 374050272621 |
10 | 120124432423 |
11 | 46a43124036 |
12 | 1b345519b47 |
13 | b434c03918 |
14 | 5b57a97739 |
15 | 31d0d8464d |
hex | 1bf7f96027 |
120124432423 has 2 divisors, whose sum is σ = 120124432424. Its totient is φ = 120124432422.
The previous prime is 120124432381. The next prime is 120124432501. The reversal of 120124432423 is 324234421021.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 120124432423 - 233 = 111534497831 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 120124432391 and 120124432400.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (120124432123) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60062216211 + 60062216212.
It is an arithmetic number, because the mean of its divisors is an integer number (60062216212).
Almost surely, 2120124432423 is an apocalyptic number.
120124432423 is a deficient number, since it is larger than the sum of its proper divisors (1).
120124432423 is an equidigital number, since it uses as much as digits as its factorization.
120124432423 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 9216, while the sum is 28.
Adding to 120124432423 its reverse (324234421021), we get a palindrome (444358853444).
The spelling of 120124432423 in words is "one hundred twenty billion, one hundred twenty-four million, four hundred thirty-two thousand, four hundred twenty-three".
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