1201254441351 has 4 divisors (see below), whose sum is σ = 1601672588472. Its totient is φ = 800836294232.

The previous prime is 1201254441313. The next prime is 1201254441353. The reversal of 1201254441351 is 1531444521021.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1201254441351 - 2¹⁴ = 1201254424967 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1201254441353) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 200209073556 + ... + 200209073561.

It is an arithmetic number, because the mean of its divisors is an integer number (400418147118).

Almost surely, 2^{1201254441351} is an apocalyptic number.

1201254441351 is a deficient number, since it is larger than the sum of its proper divisors (400418147121).

1201254441351 is an equidigital number, since it uses as much as digits as its factorization.

1201254441351 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 400418147120.

The product of its (nonzero) digits is 19200, while the sum is 33.

Adding to 1201254441351 its reverse (1531444521021), we get a palindrome (2732698962372).

The spelling of 1201254441351 in words is "one trillion, two hundred one billion, two hundred fifty-four million, four hundred forty-one thousand, three hundred fifty-one".