Base | Representation |
---|---|
bin | 11011010100000111110001… |
… | …111110001001100010011111 |
3 | 120202100022112020112100100012 |
4 | 123110013301332021202133 |
5 | 111221202214433343004 |
6 | 1103254543213553435 |
7 | 34206051246135311 |
oct | 3324076176114237 |
9 | 522308466470305 |
10 | 120129999902879 |
11 | 3530593518737a |
12 | 11581bb9aa587b |
13 | 5205297299225 |
14 | 21944745117b1 |
15 | dd4ccc49a46e |
hex | 6d41f1f8989f |
120129999902879 has 2 divisors, whose sum is σ = 120129999902880. Its totient is φ = 120129999902878.
The previous prime is 120129999902833. The next prime is 120129999902881. The reversal of 120129999902879 is 978209999921021.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 120129999902879 - 228 = 120129731467423 is a prime.
Together with 120129999902881, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (120129999982879) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60064999951439 + 60064999951440.
It is an arithmetic number, because the mean of its divisors is an integer number (60064999951440).
Almost surely, 2120129999902879 is an apocalyptic number.
120129999902879 is a deficient number, since it is larger than the sum of its proper divisors (1).
120129999902879 is an equidigital number, since it uses as much as digits as its factorization.
120129999902879 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 238085568, while the sum is 77.
The spelling of 120129999902879 in words is "one hundred twenty trillion, one hundred twenty-nine billion, nine hundred ninety-nine million, nine hundred two thousand, eight hundred seventy-nine".
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