120130002001212 has 192 divisors, whose sum is σ = 327421659801600. Its totient is φ = 33572741529600.

The previous prime is 120130002001193. The next prime is 120130002001231. The reversal of 120130002001212 is 212100200031021.

120130002001212 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is an interprime number because it is at equal distance from previous prime (120130002001193) and next prime (120130002001231).

It is a super-3 number, since 3×120130002001212³ (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 120130002001191 and 120130002001200.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 1422473164 + ... + 1422557612.

It is an arithmetic number, because the mean of its divisors is an integer number (1705321144800).

Almost surely, 2^{120130002001212} is an apocalyptic number.

120130002001212 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 120130002001212, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (163710829900800).

120130002001212 is an abundant number, since it is smaller than the sum of its proper divisors (207291657800388).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

120130002001212 is a wasteful number, since it uses less digits than its factorization.

120130002001212 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 86412 (or 86410 counting only the distinct ones).

The product of its (nonzero) digits is 48, while the sum is 15.

Adding to 120130002001212 its reverse (212100200031021), we get a palindrome (332230202032233).

The spelling of 120130002001212 in words is "one hundred twenty trillion, one hundred thirty billion, two million, one thousand, two hundred twelve".