1201300100113 has 8 divisors (see below), whose sum is σ = 1203783441408. Its totient is φ = 1198819286784.

The previous prime is 1201300100087. The next prime is 1201300100149. The reversal of 1201300100113 is 3110010031021.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1201300100113 - 2¹⁷ = 1201299969041 is a prime.

It is a super-2 number, since 2×1201300100113² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1201300100093 and 1201300100102.

It is not an unprimeable number, because it can be changed into a prime (1201300100213) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 320881 + ... + 1582897.

It is an arithmetic number, because the mean of its divisors is an integer number (150472930176).

Almost surely, 2^{1201300100113} is an apocalyptic number.

It is an amenable number.

1201300100113 is a deficient number, since it is larger than the sum of its proper divisors (2483341295).

1201300100113 is a wasteful number, since it uses less digits than its factorization.

1201300100113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1263983.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 1201300100113 its reverse (3110010031021), we get a palindrome (4311310131134).

The spelling of 1201300100113 in words is "one trillion, two hundred one billion, three hundred million, one hundred thousand, one hundred thirteen".