12013010400301 has 4 divisors (see below), whose sum is σ = 12645274105600. Its totient is φ = 11380746695004.

The previous prime is 12013010400257. The next prime is 12013010400343. The reversal of 12013010400301 is 10300401031021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12013010400301 - 2²⁹ = 12012473529389 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12013010400901) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 316131852621 + ... + 316131852658.

It is an arithmetic number, because the mean of its divisors is an integer number (3161318526400).

Almost surely, 2^{12013010400301} is an apocalyptic number.

It is an amenable number.

12013010400301 is a deficient number, since it is larger than the sum of its proper divisors (632263705299).

12013010400301 is an equidigital number, since it uses as much as digits as its factorization.

12013010400301 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 632263705298.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 12013010400301 its reverse (10300401031021), we get a palindrome (22313411431322).

The spelling of 12013010400301 in words is "twelve trillion, thirteen billion, ten million, four hundred thousand, three hundred one".