1201302020021 has 2 divisors, whose sum is σ = 1201302020022. Its totient is φ = 1201302020020.

The previous prime is 1201302019991. The next prime is 1201302020057. The reversal of 1201302020021 is 1200202031021.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 921552000625 + 279750019396 = 959975^2 + 528914^2 .

It is a cyclic number.

It is not a de Polignac number, because 1201302020021 - 2¹⁴ = 1201302003637 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 1201302019978 and 1201302020005.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1201302020221) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600651010010 + 600651010011.

It is an arithmetic number, because the mean of its divisors is an integer number (600651010011).

Almost surely, 2^{1201302020021} is an apocalyptic number.

It is an amenable number.

1201302020021 is a deficient number, since it is larger than the sum of its proper divisors (1).

1201302020021 is an equidigital number, since it uses as much as digits as its factorization.

1201302020021 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48, while the sum is 14.

Adding to 1201302020021 its reverse (1200202031021), we get a palindrome (2401504051042).

The spelling of 1201302020021 in words is "one trillion, two hundred one billion, three hundred two million, twenty thousand, twenty-one".