Base | Representation |
---|---|
bin | 1010111011010000000110… |
… | …0101010111101001010110 |
3 | 1120112102210010010212221222 |
4 | 2232310001211113221112 |
5 | 3033310211311202220 |
6 | 41314415151010342 |
7 | 2346625403023130 |
oct | 256640145275126 |
9 | 46472703125858 |
10 | 12013050100310 |
11 | 3911784669376 |
12 | 14202622099b2 |
13 | 691a9728352c |
14 | 2d7612c6a050 |
15 | 15c74896be25 |
hex | aed01957a56 |
12013050100310 has 32 divisors (see below), whose sum is σ = 24742370410560. Its totient is φ = 4113791667072.
The previous prime is 12013050100309. The next prime is 12013050100339. The reversal of 12013050100310 is 1300105031021.
12013050100310 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a super-2 number, since 2×120130501003102 (a number of 27 digits) contains 22 as substring.
It is a Curzon number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 103449209 + ... + 103565268.
It is an arithmetic number, because the mean of its divisors is an integer number (773199075330).
Almost surely, 212013050100310 is an apocalyptic number.
12013050100310 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
12013050100310 is an abundant number, since it is smaller than the sum of its proper divisors (12729320310250).
12013050100310 is a wasteful number, since it uses less digits than its factorization.
12013050100310 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 207015320.
The product of its (nonzero) digits is 90, while the sum is 17.
Adding to 12013050100310 its reverse (1300105031021), we get a palindrome (13313155131331).
The spelling of 12013050100310 in words is "twelve trillion, thirteen billion, fifty million, one hundred thousand, three hundred ten".
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