Base | Representation |
---|---|
bin | 100011110011010… |
… | …1000100110100001 |
3 | 10002201110212200011 |
4 | 1013212220212201 |
5 | 4430013410423 |
6 | 315112124521 |
7 | 41524652563 |
oct | 10746504641 |
9 | 3081425604 |
10 | 1201310113 |
11 | 567121083 |
12 | 296396741 |
13 | 161b628b3 |
14 | b5791333 |
15 | 706e8b0d |
hex | 479a89a1 |
1201310113 has 2 divisors, whose sum is σ = 1201310114. Its totient is φ = 1201310112.
The previous prime is 1201310111. The next prime is 1201310147. The reversal of 1201310113 is 3110131021.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1092170304 + 109139809 = 33048^2 + 10447^2 .
It is an emirp because it is prime and its reverse (3110131021) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1201310113 - 21 = 1201310111 is a prime.
Together with 1201310111, it forms a pair of twin primes.
It is a junction number, because it is equal to n+sod(n) for n = 1201310093 and 1201310102.
It is not a weakly prime, because it can be changed into another prime (1201310111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600655056 + 600655057.
It is an arithmetic number, because the mean of its divisors is an integer number (600655057).
Almost surely, 21201310113 is an apocalyptic number.
It is an amenable number.
1201310113 is a deficient number, since it is larger than the sum of its proper divisors (1).
1201310113 is an equidigital number, since it uses as much as digits as its factorization.
1201310113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18, while the sum is 13.
The square root of 1201310113 is about 34659.9208452645. The cubic root of 1201310113 is about 1063.0451515332.
Adding to 1201310113 its reverse (3110131021), we get a palindrome (4311441134).
The spelling of 1201310113 in words is "one billion, two hundred one million, three hundred ten thousand, one hundred thirteen".
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