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1201310120123 = 5992005526077
BaseRepresentation
bin10001011110110011101…
…010011011100010111011
311020211210100221002220222
4101132303222123202323
5124140240342320443
62315512501010255
7152535404353151
oct21366352334273
94224710832828
101201310120123
114235222767a3
121749a43b398b
138938ab57109
14422025213d1
15213aec29468
hex117b3a9b8bb

1201310120123 has 4 divisors (see below), whose sum is σ = 1203315646800. Its totient is φ = 1199304593448.

The previous prime is 1201310120089. The next prime is 1201310120159. The reversal of 1201310120123 is 3210210131021.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1201310120123 - 234 = 1184130250939 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1201310120323) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1002762440 + ... + 1002763637.

It is an arithmetic number, because the mean of its divisors is an integer number (300828911700).

Almost surely, 21201310120123 is an apocalyptic number.

1201310120123 is a deficient number, since it is larger than the sum of its proper divisors (2005526677).

1201310120123 is an equidigital number, since it uses as much as digits as its factorization.

1201310120123 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2005526676.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 1201310120123 its reverse (3210210131021), we get a palindrome (4411520251144).

The spelling of 1201310120123 in words is "one trillion, two hundred one billion, three hundred ten million, one hundred twenty thousand, one hundred twenty-three".

Divisors: 1 599 2005526077 1201310120123