Base | Representation |
---|---|
bin | 10110011000000100… |
… | …10110000100000000 |
3 | 1011000012202202222020 |
4 | 23030002112010000 |
5 | 144100323220222 |
6 | 5304014241440 |
7 | 603460450662 |
oct | 131402260400 |
9 | 34005682866 |
10 | 12013101312 |
11 | 510509a903 |
12 | 23b31b6280 |
13 | 1195aa0b94 |
14 | 81d66c532 |
15 | 4a49ac65c |
hex | 2cc096100 |
12013101312 has 36 divisors (see below), whose sum is σ = 31972370640. Its totient is φ = 4004366848.
The previous prime is 12013101293. The next prime is 12013101343. The reversal of 12013101312 is 21310131021.
It is a happy number.
It is a super-2 number, since 2×120131013122 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 12013101291 and 12013101300.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7820262 + ... + 7821797.
Almost surely, 212013101312 is an apocalyptic number.
12013101312 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
12013101312 is an abundant number, since it is smaller than the sum of its proper divisors (19959269328).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
12013101312 is an equidigital number, since it uses as much as digits as its factorization.
12013101312 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 15642078 (or 15642064 counting only the distinct ones).
The product of its (nonzero) digits is 36, while the sum is 15.
Adding to 12013101312 its reverse (21310131021), we get a palindrome (33323232333).
The spelling of 12013101312 in words is "twelve billion, thirteen million, one hundred one thousand, three hundred twelve".
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