120131020193 has 2 divisors, whose sum is σ = 120131020194. Its totient is φ = 120131020192.

The previous prime is 120131020151. The next prime is 120131020223. The reversal of 120131020193 is 391020131021.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 118083638689 + 2047381504 = 343633^2 + 45248^2 .

It is a cyclic number.

It is not a de Polignac number, because 120131020193 - 2⁸ = 120131019937 is a prime.

It is a super-2 number, since 2×120131020193² (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (120131020133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60065510096 + 60065510097.

It is an arithmetic number, because the mean of its divisors is an integer number (60065510097).

Almost surely, 2^120131020193 is an apocalyptic number.

It is an amenable number.

120131020193 is a deficient number, since it is larger than the sum of its proper divisors (1).

120131020193 is an equidigital number, since it uses as much as digits as its factorization.

120131020193 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 324, while the sum is 23.

The spelling of 120131020193 in words is "one hundred twenty billion, one hundred thirty-one million, twenty thousand, one hundred ninety-three".